Resolve quadratic trinomials into factors: 3x2 + 10x + 3
We have,
3x2 + 10x + 3
The coefficient of x2 is 3
The coefficient of x is 10
Constant term is 3
So, we express the middle term 10x as 9x + x
3x2 + 10x + 3 = 3x2 + 9x + x + 3
= 3x (x + 3) + 1 (x + 3)
= (3x + 1) (x + 3)
Divide as directed (x4 – 81) ÷ (x3 + 3x2 + 9x + 27)
Divide as directed (3x3 – 6x2 – 24x) ÷ (x – 4) (x + 2)
Divide as directed 15(y + 3)(y2 – 16) ÷ 5(y2 – y – 12)
Factorise x2 + 2xy – 99y2
Factorise 6x2 – 5xy – 6y2