We have,

3 + 23y – 8y^{2}

– 8y^{2} + 23y + 3

8y^{2} – 23y – 3

The coefficient of y^{2} is 8

The coefficient of y is -23

Constant term is -3

So, we express the middle term -23y as -24y + y

8y^{2} – 23y – 3 = 8y^{2} – 24y + y – 3

= 8y (y – 3) + 1 (y – 3)

= (8y + 1) (y – 3)

Answered by Aaryan | 1 year agoDivide as directed (x^{4} – 81) ÷ (x^{3} + 3x^{2} + 9x + 27)

Divide as directed (3x^{3} – 6x^{2} – 24x) ÷ (x – 4) (x + 2)

Divide as directed 15(y + 3)(y^{2} – 16) ÷ 5(y^{2} – y – 12)