Resolve quadratic trinomials into factors: 3 + 23y – 8y2

We have,

3 + 23y – 8y²

– 8y² + 23y + 3

8y² – 23y – 3

The coefficient of y² is 8

The coefficient of y is -23

Constant term is -3

So, we express the middle term -23y as -24y + y

8y² – 23y – 3 = 8y² – 24y + y – 3

= 8y (y – 3) + 1 (y – 3)

= (8y + 1) (y – 3)