Sum of \(\dfrac{ – 5 }{ 7} and \dfrac{ – 8 }{ 3}\) can be calculated as,
\( \dfrac{ – 5 }{ 7} and \dfrac{ – 8 }{ 3}\) = \( \dfrac{ – 5 }{ 7} + \dfrac{ – 8 }{ 3}\)
On further calculation, we get
= \(\dfrac { (- 15 – 56) }{ 21}\)
= \( \dfrac{ – 71 }{ 21} \)
Now,
Sum of \( \dfrac{ 5 }{ 2} and \dfrac{ – 11 }{ 12}\) can be calculated as,
\( \dfrac{ 5 }{ 2}+ \dfrac{ – 11 }{ 12}\) = \( \dfrac{ 5 }{ 2} - \dfrac{ 11 }{ 12}\)
On simplification, we get,
= \(\dfrac{ (30 – 11) }{ 12}\)
= \( \dfrac{ 19 }{12} \)
Now,
\( \dfrac{ 19 }{12} \) – (\( \dfrac{ -71 }{21} \))
= \( \dfrac{ 19 }{12} \) + \( \dfrac{ 71 }{21} \)
Taking L.C.M. we get,
= \(\dfrac{ (133 + 284) }{ 84}\)
= \( \dfrac{ 417 }{ 84}\)
= \(4 \dfrac{81 }{ 84}\)
Answered by Aaryan | 1 year agoBy what number should 1365 be divided to get 31 as quotient and 32 as remainder?
Which of the following statement is true / false?
(i) \(\dfrac{ 2 }{ 3} – \dfrac{4 }{ 5}\) is not a rational number.
(ii) \( \dfrac{ -5 }{ 7}\) is the additive inverse of \( \dfrac{ 5 }{ 7}\)
(iii) 0 is the additive inverse of its own.
(iv) Commutative property holds for subtraction of rational numbers.
(v) Associative property does not hold for subtraction of rational numbers.
(vi) 0 is the identity element for subtraction of rational numbers.
If x = \( \dfrac{4 }{ 9}\), y =\( \dfrac{-7 }{ 12}\) and z = \( \dfrac{-2 }{ 3}\), then verify that x – (y – z) ≠ (x – y) – z
If x = \(\dfrac{ – 4 }{ 7}\) and y = \( \dfrac{2 }{ 5}\), then verify that x – y ≠ y – x
What rational number should be subtracted from \(-4 \dfrac{3 }{5}\) to get \( -3 \dfrac{1 }{2}\)