Subtract the sum of $$\dfrac{ – 5 }{ 7} and\dfrac{ – 8 }{ 3}$$ from the sum of $$\dfrac{5 }{ 2} and \dfrac{– 11 }{ 12}$$

Asked by Sakshi | 1 year ago |  215

##### Solution :-

Sum of $$\dfrac{ – 5 }{ 7} and \dfrac{ – 8 }{ 3}$$ can be calculated as,

$$\dfrac{ – 5 }{ 7} and \dfrac{ – 8 }{ 3}$$ = $$\dfrac{ – 5 }{ 7} + \dfrac{ – 8 }{ 3}$$

On further calculation, we get

= $$\dfrac { (- 15 – 56) }{ 21}$$

$$\dfrac{ – 71 }{ 21}$$

Now,

Sum of $$\dfrac{ 5 }{ 2} and \dfrac{ – 11 }{ 12}$$ can be calculated as,

$$\dfrac{ 5 }{ 2}+ \dfrac{ – 11 }{ 12}$$ = $$\dfrac{ 5 }{ 2} - \dfrac{ 11 }{ 12}$$

On simplification, we get,

= $$\dfrac{ (30 – 11) }{ 12}$$

$$\dfrac{ 19 }{12}$$

Now,

$$\dfrac{ 19 }{12}$$ – ($$\dfrac{ -71 }{21}$$)

= $$\dfrac{ 19 }{12}$$ + $$\dfrac{ 71 }{21}$$

Taking L.C.M. we get,

= $$\dfrac{ (133 + 284) }{ 84}$$

$$\dfrac{ 417 }{ 84}$$

$$4 \dfrac{81 }{ 84}$$

Answered by Aaryan | 1 year ago

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