Given: Dividend = 1365, Quotient = 31 and Remainder = 32
Let us consider, Divisor as a number y.
To Find: The value of y
As per Euclid's lemma, we have
Dividend = \( (divisor \times quotient) + remainder\)
After substituting the values, we get
1365 = (y × 31) + 32
1365 - 32 = 31y
1333 = 31y
or y =\(\dfrac{ 1333}{31}\) = 43
So, 1365 should be divided by 43 to get 31 as quotient and 32 as remainder.
Answered by Sakshi | 1 year agoWhich of the following statement is true / false?
(i) \(\dfrac{ 2 }{ 3} – \dfrac{4 }{ 5}\) is not a rational number.
(ii) \( \dfrac{ -5 }{ 7}\) is the additive inverse of \( \dfrac{ 5 }{ 7}\)
(iii) 0 is the additive inverse of its own.
(iv) Commutative property holds for subtraction of rational numbers.
(v) Associative property does not hold for subtraction of rational numbers.
(vi) 0 is the identity element for subtraction of rational numbers.
If x = \( \dfrac{4 }{ 9}\), y =\( \dfrac{-7 }{ 12}\) and z = \( \dfrac{-2 }{ 3}\), then verify that x – (y – z) ≠ (x – y) – z
If x = \(\dfrac{ – 4 }{ 7}\) and y = \( \dfrac{2 }{ 5}\), then verify that x – y ≠ y – x
Subtract the sum of \(\dfrac{ – 5 }{ 7} and\dfrac{ – 8 }{ 3}\) from the sum of \(\dfrac{5 }{ 2} and \dfrac{– 11 }{ 12}\)
What rational number should be subtracted from \(-4 \dfrac{3 }{5}\) to get \( -3 \dfrac{1 }{2}\)