Given: Dividend = 1365, Quotient = 31 and Remainder = 32

Let us consider, Divisor as a number y.

To Find: The value of y

As per Euclid's lemma, we have

Dividend = \( (divisor \times quotient) + remainder\)

After substituting the values, we get

1365 = (y × 31) + 32

1365 - 32 = 31y

1333 = 31y

or y =\(\dfrac{ 1333}{31}\) = 43

So, 1365 should be divided by 43 to get 31 as quotient and 32 as remainder.

Answered by Sakshi | 1 year agoWhich of the following statement is true / false?

**(i)** \(\dfrac{ 2 }{ 3} – \dfrac{4 }{ 5}\) is not a rational number.

**(ii) **\( \dfrac{ -5 }{ 7}\) is the additive inverse of \( \dfrac{ 5 }{ 7}\)

**(iii)** 0 is the additive inverse of its own.

**(iv) **Commutative property holds for subtraction of rational numbers.

**(v) **Associative property does not hold for subtraction of rational numbers.

**(vi)** 0 is the identity element for subtraction of rational numbers.

If x = \( \dfrac{4 }{ 9}\), y =\( \dfrac{-7 }{ 12}\) and z = \( \dfrac{-2 }{ 3}\), then verify that x – (y – z) ≠ (x – y) – z

If x = \(\dfrac{ – 4 }{ 7}\) and y = \( \dfrac{2 }{ 5}\), then verify that x – y ≠ y – x

Subtract the sum of \(\dfrac{ – 5 }{ 7} and\dfrac{ – 8 }{ 3}\) from the sum of \(\dfrac{5 }{ 2} and \dfrac{– 11 }{ 12}\)

What rational number should be subtracted from \(-4 \dfrac{3 }{5}\)** **to get** **\( -3 \dfrac{1 }{2}\)