Speed of sound (v) = 342 \( ms^{-1}\)
Echo returns in time (t) = 3 s
Distance travelled by sound = v × t = 342 × 3 = 1026 m
In the given interval of time, sound must travel a distance which is twice the distance of reflecting surface and source.
Therefore, the distance of reflecting surface from the source = \( \frac{1026}{513}\) = 513 m.
Answered by Vishal kumar | 2 years agoExplain how defects in a metal block can be detected using ultrasound.
A sonar device on a submarine sends out a signal and receives an echo 5 s later. Calculate the speed of sound in water if the distance of the object from the submarine is 3625 m.