A stone is dropped from the top of a tower 500 m high into a pond of water at the base of the tower. When is the splash heard at the top? Given, g = 10 m s-2 and speed of sound = 340 m s-1 .

Asked by Vishal kumar | 2 years ago |  162

1 Answer

Solution :-

Height (s) of tower = 500 m

Velocity (v) of sound = 340 m s-1

Acceleration (g) due to gravity = 10 m s-1

Initial velocity (u) of the stone = 0

Time (t1) taken by the stone to fall to tower base

As per second equation of motion:

s= ut1 + (½) g (t12

500 = 0 x t1 + (½) 10 (t12

(t1)2 = 100

t1 = 10 s

Time (t2) taken by sound to reach top from tower base = 500/340 = 1.47 s.

t = t1 + t2

t = 10 + 1.47

t = 11.47 s.

Answered by Shivani Kumari | 2 years ago

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