Time (t) taken to hear the echo = 5 s
Distance (d) of object from submarine = 3625 m
Total distance travelled by SONAR during reception and transmission in water = 2d
Velocity (v) of sound in water = \( \frac{2d}{t}=\frac{(2\times 3625)}{5}\)
= 1450 ms-1
Answered by Vishal kumar | 2 years ago