From Newton’s law of gravitation, we know that the force of attraction between the bodies is given by

F = \( \frac{(Gm_1m_2)}{r^2}\)

Here

m_{1 = mass of earth = 6.0 \( \times\)1024}kg

m_{2 = mass of the body = 1kg}

_{r = distance between the two bodies}

_{Radius of Earth = 6.4 \( \times\)} 10^{6}m

G = Universal gravitational constant = 6.67 \( \times\)10^{-11} Nm^{2}kg^{-2}

^{By substituting all the values in the equation}

^{F = \(\frac{(Gm_1m_2)}{r^2}\)}

F \(= \frac{6.67\times 10^{11}(6.0\times 10^{24}\times 1)}{(6.4\times 10^6)^2}\)

F = 9.8 N

This shows that Earth exerts a force o 9.8 N on a body of mass 1 Kg. The body will exerts an equal force of attraction of 9.8 N on the Earth.

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