A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity just before touching the ground.

Asked by Shivani Kumari | 1 year ago |  202

1 Answer

Solution :-

Given data:

Initial velocity

u = 0

wer height = total distance = 19.6m

g = 9.8 m/s2

Consider third equation of motion

v2 = u2 + 2gs

v2 = 0 + 2 × 9.8 × 19.6

v2 = 384.16

v = √(384.16)

v = 19.6m/s

Answered by Vishal kumar | 1 year ago

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