11.00g of carbon dioxide is formed when 3.00g of carbon is burnt in 8.00g of oxygen.
Carbon and oxygen are combined in the ratio 3:8 to give carbon dioxide, using up all the carbon and oxygen
Hence, for 3g of carbon and 50g of oxygen, 8g of oxygen is used and 11g of carbon is formed, the
left oxygen is unused, i.e., 50-3=47g of oxygen is unused.
This depicts the law of definite proportions - The combining elements in compounds are present in definite proportions by mass
Answered by Shivani Kumari | 1 year agoCalculate the number of aluminium ions present in 0.051g of aluminium oxide.
(Hint: The mass of an ion is the same as that of an atom of the same element. Atomic mass of Al = 27u)
Calculate the number of molecules of sulphur (S8) present in 16g of solid sulphur.
What is the mass of:
(a) 0.2 mole of oxygen atoms?
(b) 0.5 mole of water molecules?
Convert into mole.
(a) 12g of oxygen gas
(b) 20g of water
(c) 22g of carbon dioxide
What is the mass of -
(a) 1 mole of nitrogen atoms?
(b) 4 moles of aluminium atoms((Atomic mass of aluminium =27)?
(c) 10 moles of sodium sulphite (Na2SO3)?