Given that the signal travels in a straight line, the distance between the spaceship and the ground station is equal to the total distance travelled by the signal.
5 minutes = 5*60 seconds = 300 seconds.
Speed of the signal = 3 × 108 m/s.
Therefore, total distance = (3 × 108 m/s) * 300s
= 9*1010 meters.
Answered by Shivani Kumari | 1 year agoA bus starting from rest moves with a uniform acceleration of 0.1 m s-2 for 2 minutes. Find
(a) the speed acquired,
(b) the distance traveled.
A farmer moves along the boundary of a square field of side 10m in 40 s. What will be the magnitude of displacement of the farmer at the end of 2 minutes 20 seconds from his initial position?
What is the quantity which is measured by the area occupied below the velocity-time graph?
A bus starting from rest moves with a uniform acceleration of 0.1 m s-2 for 2 minutes. Find
(a) the speed acquired,
(b) the distance travelled.
What can you say about the motion of an object if its speed-time graph is a straight line parallel to the time axis?