The kinetic energy of an object of mass, m moving with a velocity of 5 ms-1 is 25 J. What will be its kinetic energy when its velocity is doubled? What will be its kinetic energy when its velocity is increased three times?

Asked by Vishal kumar | 1 year ago |  185

##### Solution :-

The kinetic energy of the object = 25 j

The formula for kinetic energy is

Kinetic energy$$= \frac{mv^2}{2}$$

m = 2 kg

Therefore, increased velocity = $$(3\times5)\frac{m}{s}=15m/s$$

Kinetic energy increase = $$\frac{1}{2}\times2\times(15)^2 = 225j$$

Answered by Shivani Kumari | 1 year ago

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