Given Mass (m) = 40 kg

Acceleration due to gravity = (g) = 10 m/s^{2}

^{Height (h) = 5 m}

^{Potential energy = \(m\, \times\,g\,\times\,h\)}

P.E = \( 40\,\times\,10\,\times\,5\,=\,200J\)

potential energy = 2000 J (2000 joules)

At a height of 5 metre, the object has a potential energy of 2000 J.

When this object is allowed to fall, and it is Halfway down its height above the ground will be half of 5 m = \( 5\,m=\,\frac{5}{2}=\,2.5\,m\)

P.E at Halfway down = ^{\(m\, \times\,g\,\times\,h\)}

P.E = \( 40\,\times\,10\,\times\,2.5\,=\,1000J\)

{h =2.5 m}

Potential Energy at halfway down = 1000 joules

According to law of conservation of energy

Total potential energy = potential energy at Halfway down + kinetic energy at Halfway of a down 2000 = 1000 + K.E at Halfway down

K.E at Half down = 2000 - 1000 = 1000 J

Kinetic energy at halfway down = 1000 joules.

Answered by Shivani Kumari | 1 year ago

A freely falling object eventually stops on reaching the ground. What happens to its kinetic energy?

Find the energy in kW h consumed in 10 hours by four devices of power 500 W

each

Soni says that the acceleration in an object could be zero even when several forces are acting on it. Do you agree with her? Why?

In each of the following a force, F is acting on an object of mass, m. The direction of displacement is from west to east shown by the longer arrow. Observe the diagrams carefully and state whether the work done by the force is negative, positive

Calculate the work required to be done to stop a car of 1500 kg moving at a velocity of 60 km/h?