Given data:

The mass of the body = 1500 kg

Velocity v = 60 km/hr

\( = \frac{60\,\times\,100m}{3600s}\)

\( = \frac{50}{3}\,m/s\)

The work required to stop the car = kinetic energy change of the car

\( = \frac{1}{2}\,mv^2\,-\, \frac{1}{2}m(0)^2\)

\( = \frac{1}{2}\,\times\,(1500)\,\times(\frac{50}{3})^2\)

208333.3 J

Answered by Shivani Kumari | 2 years agoA freely falling object eventually stops on reaching the ground. What happens to its kinetic energy?

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