From a rifle of mass 4 kg, a bullet of mass 50 g is fired with an initial velocity of 35 m s –1 . Calculate the initial recoil velocity of the rifle.

Asked by Vishal kumar | 2 years ago |  272

##### Solution :-

Given, the Bullet’s mass (m1) = 50 g

The rifle’s mass (m2) = 4 kg = 4000g

Initial velocity of the fired bullet (v1) = 35 m/s

Let the recoil

velocity be v2.

Since the rifle was initially at rest, the initial momentum of the rifle = 0

Total momentum of the rifle and bullet after firing = m1v1 + m2v2

As per the law of conservation of momentum, the total momentum of the rifle and the bullet after firing = 0 (same as initial momentum)

Therefore, m1v1 + m2v2 = 0

$$This \,implies \,that\, v_2 = -\frac{m_1v_1}{m_2}$$

$$= -\frac{50g\,\times \, 35ms^{-1}}{4000g}$$

= - 0.4375 m/s

Therefore, the recoil velocity of the rifle is 0.4375 meters per second in the direction opposite to the trajectory of the bullet (backward direction).

Answered by Vishal kumar | 2 years ago

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