Given, distance covered by the truck (s) = 400 meters
Time taken to cover the distance (t) = 20 seconds
Initial velocity of the truck (u) = 0 (since it starts from a state of rest)
From the equations of motion, \(s\,=\,ut+\frac{1}{2}at^2\)
\(Therefore,400 = 0(20s) + \frac{1}{2}(a)(400s^2) = 2ms^{-2}\)
The acceleration of the truck is equal to 2ms-2
As per the second law of motion, force = \(Mass\,\times\,Acceleration\)
Mass of the truck = 7 tonnes = 7000 kg
Force acting on the truck = 7000 kg \( \times\) 2 m.s-1 = 14000 kg.m.s-2 = 14000 N
Therefore, a force of 14000 N is acting on the truck.
Answered by Shivani Kumari | 2 years agoA motorcar of mass 1200 kg is moving along a straight line with a uniform velocity of 90 km/h. Its velocity is slowed down to 18 km/h in 4 s by an unbalanced external force. Calculate the acceleration and change in momentum. Also calculate the magnitude of the force required
A hammer of mass 500 g, moving at 50 m s-1, strikes a nail. The nail stops the hammer in a very short time of 0.01 s. What is the force of the nail on the hammer
Two persons manage to push a motorcar of mass 1200 kg at a uniform velocity along a level road. The same motorcar can be pushed by three persons to produce an acceleration of 0.2 m s-2. With what force does each person push the motorcar? (Assume that all persons push the motorcar with the same muscular effort)
The following is the distance-time table of an object in motion:
| Time (seconds) | Distance (meters) |
| 0 | 0 |
| 1 | 1 |
| 2 | 8 |
| 3 | 27 |
| 4 | 84 |
| 5 | 125 |
| 6 | 216 |
| 7 | 343 |
(a) What conclusion can you draw about the acceleration? Is it constant, increasing, decreasing, or zero?
(b) What do you infer about the forces acting on the object?
How much momentum will a dumb-bell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be 10 ms–2 .