Two objects, each of mass 1.5 kg, are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 ms -1 before the collision during which they stick together. What will be the velocity of the combined object after collision?
Given, the mass of the
objects (m1 and m2) = 1.5 kg
Initial velocity of the first object (u1) = 2.5 m/s
Initial velocity of the second object, which is moving in the opposite direction (u2) = -2.5 m/s
When the two masses stick together, the resulting object has a mass of 3 kg (m1 + m2)
Velocity of the resulting object (v) =?
As per the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.
Total momentum before the collision = m1u1 + m2u2
= (1.5 kg) (2.5 m/s) + (1.5 kg) (-2.5 m/s) = 0
Therefore, total momentum after collision = (m1+m2) v = (3 kg) v = 0
Therefore, v = 0
This implies that the object formed after the collision has a velocity of 0 meters per second.Answered by Vishal kumar | 2 years ago
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