Two objects, each of mass 1.5 kg, are moving in the same straight line but in opposite directions. The velocity of each object is 2.5 ms -1 before the collision during which they stick together. What will be the velocity of the combined object after collision?

Asked by Vishal kumar | 1 year ago |  223

1 Answer

Solution :-

Given, the mass of the

objects (m1 and m2) = 1.5 kg

Initial velocity of the first object (u1) = 2.5 m/s

Initial velocity of the second object, which is moving in the opposite direction (u2) = -2.5 m/s

When the two masses stick together, the resulting object has a mass of 3 kg (m1 + m2)

Velocity of the resulting object (v) =?

As per the law of conservation of momentum, the total momentum before the collision is equal to the total momentum after the collision.

Total momentum before the collision = m1u1 + m2u2

= (1.5 kg) (2.5 m/s) + (1.5 kg) (-2.5 m/s) = 0

Therefore, total momentum after collision = (m1+m2) v = (3 kg) v = 0

Therefore, v = 0

This implies that the object formed after the collision has a velocity of 0 meters per second.

Answered by Vishal kumar | 1 year ago

Related Questions

A motorcar of mass 1200 kg is moving along a straight line with a uniform velocity of 90 km/h. Its velocity is slowed down to 18 km/h in 4 s by an unbalanced external force. Calculate the acceleration and change in momentum. Also calculate the magnitude of the force required

Class 9 Science Force and Laws of Motion View Answer

A hammer of mass 500 g, moving at 50 m s-1, strikes a nail. The nail stops the hammer in a very short time of 0.01 s. What is the force of the nail on the hammer

Class 9 Science Force and Laws of Motion View Answer

Two persons manage to push a motorcar of mass 1200 kg at a uniform velocity along a level road. The same motorcar can be pushed by three persons to produce an acceleration of 0.2 m s-2. With what force does each person push the motorcar? (Assume that all persons push the motorcar with the same muscular effort)

Class 9 Science Force and Laws of Motion View Answer

The following is the distance-time table of an object in motion:

Time (seconds) Distance (meters)
0 0
1 1
2 8
3 27
4 84
5 125
6 216
7 343

(a) What conclusion can you draw about the acceleration? Is it constant, increasing, decreasing, or zero?

(b) What do you infer about the forces acting on the object?

Class 9 Science Force and Laws of Motion View Answer

How much momentum will a dumb-bell of mass 10 kg transfer to the floor if it falls from a height of 80 cm? Take its downward acceleration to be 10 ms–2 .

Class 9 Science Force and Laws of Motion View Answer