A hockey ball of mass 200 g travelling at 10 ms –1 is struck by a hockey stick so as to return it along its original path with a velocity at 5 ms –1 . Calculate the magnitude of change of momentum occurred in the motion of the hockey ball by the force applied by the hockey stick.

Asked by Vishal kumar | 2 years ago |  310

##### Solution :-

Given, the mass of the

ball (m) = 200g

Initial velocity of the ball (u) = 10 m/s

Final velocity of the ball (v) = 5 m/s

Initial momentum of the ball = mu = 200g × 10 ms-1 = 2000 g.m.s-1

Final momentum of the ball = mv = 200g × 5 ms-1 = 1000 g.m.s-1

Therefore, the change in momentum (mv – mu) = 1000 g.m.s-1 - 2000 g.m.s-1 = -1000 g.m.s-1

This implies that the momentum of the ball reduces by 1000 g.m.s-1 after being struck by the hockey stick

Answered by Shivani Kumari | 2 years ago

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