Dogs have a certain set of genes that govern coat color. There are a minimum of eleven known sequence series (A, B, C, D, E, F, G, M, P, S, T) that influence the colour of a dog. A dog inherits one copy from each of its parents. As an example, within the B series, a dog is genetically black or brown. Assume that one parent is homozygous black (BB), whereas the other parent is homozygous brown (bb).
| bb | BB | ||
| B | B | ||
| b | Bb | Bb | |
| b | Bb | Bb | |
In this case, all the offsprings are going to be heterozygous (Bb). Since black (B) is dominant, all the offsprings are going to be black. However, they are going to have each B and b alleles. If such heterozygous pups are crossed, they are going to produce 25 homozygous blacks (BB), 15 heterozygous black (Bb), and 25 homozygous brown (bb) offsprings.
| B | b | |
| B | BB | Bb |
| b | Bb | Bb |
Answered by Vishal kumar | 2 years ago
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