Identify the substances that are oxidized and that are reduced in the following equation.

i) 4Na(s) + O2(g) → 2Na2O(s)

ii) CuO(s) + H2(g) → Cu(s) + H2O(l)

Asked by Shivani Kumari | 2 years ago |  247

1 Answer

Solution :-

The Sodium (Na) in the first equation is getting oxidized with the addition of Oxygen (O2) and the Copper (Cu) in the second equation is reduced due to the addition of Hydrogen (H2)

Answered by Vishal kumar | 2 years ago

Related Questions

Provide Some Important MCQ Questions for Class 10 Science Chemical Reactions and Equations with Answers?

Class 10 Science Chemical Reactions and Equations View Answer

Explain the following terms with one example each.

(a) Corrosion

(b) Rancidity Solution:

Class 10 Science Chemical Reactions and Equations View Answer

A shiny brown coloured element ‘X’ on heating in the air becomes black in colour. Name the element ‘X’ and the black coloured compound formed.

Class 10 Science Chemical Reactions and Equations View Answer