Given the standard electrode potentials,

\(
\dfrac{ K^{+}}{K}\)= –2.93V

\(
\dfrac{ Ag^{+}}{Ag}\) = 0.80V

\(
\dfrac{Hg^{2+}}{Hg}\) = 0.79V

\(\dfrac{ Mg^{2+}}{Mg}\) = –2.37V

\(\dfrac{Cr^{3+}}{Cr}\) = –0.74V

Arrange these metals in their increasing order of reducing power.